4. 定积分 $\int_0^{\frac{\pi}{2}} |1 - \sqrt{2} \sin x| dx = $ （）。 A. A. $\int_0^{\frac{\pi}{4}} (1 - \sqrt{2} \sin x) dx + \int_{\frac{\pi}{4}}^{\frac{\pi}{2}} (1 - \sqrt{2} \sin x) dx$ B. B. $\int_0^{\frac{\pi}{4}} (1 - \sqrt{2} \sin x) dx + \int_{\frac{\pi}{4}}^{\frac{\pi}{2}} (\sqrt{2} \sin x - 1) dx$ C. C. $\int_0^{\frac{\pi}{4}} (\sqrt{2} \sin x - 1) dx + \int_{\frac{\pi}{4}}^{\frac{\pi}{2}} (\sqrt{2} \sin x - 1) dx$ D. D. $\int_0^{\frac{\pi}{4}} (\sqrt{2} \sin x - 1) dx + \int_{\frac{\pi}{4}}^{\frac{\pi}{2}} (1 - \sqrt{2} \sin x) dx$

单选题难度 3

4. 定积分 $\int_0^{\frac{\pi}{2}} |1 - \sqrt{2} \sin x| dx =$ （）。

选项 A A. $\int_0^{\frac{\pi}{4}} (1 - \sqrt{2} \sin x) dx + \int_{\frac{\pi}{4}}^{\frac{\pi}{2}} (1 - \sqrt{2} \sin x) dx$
选项 B B. $\int_0^{\frac{\pi}{4}} (1 - \sqrt{2} \sin x) dx + \int_{\frac{\pi}{4}}^{\frac{\pi}{2}} (\sqrt{2} \sin x - 1) dx$
选项 C C. $\int_0^{\frac{\pi}{4}} (\sqrt{2} \sin x - 1) dx + \int_{\frac{\pi}{4}}^{\frac{\pi}{2}} (\sqrt{2} \sin x - 1) dx$
选项 D D. $\int_0^{\frac{\pi}{4}} (\sqrt{2} \sin x - 1) dx + \int_{\frac{\pi}{4}}^{\frac{\pi}{2}} (1 - \sqrt{2} \sin x) dx$

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